MathCamp98 Class 5

Class 5.1 Integration.

Class 5.2 Review the past exam.

Last time

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Interpretations of derivatives and the chain rule.
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Two variable calculus.

Today's class If we start off with a function f(x) we know how to find the derivative (slope) of the function.

The converse is to be given a function and ask the question: ``what was differentiated to get this function as the derivative''?

Example: what function would have as it's derivative tex2html_wrap_inline43 ?

Answer: tex2html_wrap_inline45 where c is any constant.

We call tex2html_wrap_inline45 the anti-derivative of tex2html_wrap_inline43 .

Motivation for the integral.

Consider the velocity graph.

For a small change in time the area in the rectangle equals the distance you have traveled in that time period.

The sum of the areas of the rectangles approximates how far you have traveled during the entire time period.

As the time intervals get shorter the area under the velocity curve indicates how far you have traveled.

We know the rate of change of distance is velocity.

Therefore the anti-derivative of velocity is distance.

The area under the velocity graph is distance. Therefore to find the area under the velocity function (distance traveled) you need to find the ``anti-derivative'' of the velocity function.

To find the area under the graph of f(x) you need to find the anti-derivative of f(x).

If f(x) is the function we are interested in, and F(x) is it's anti-derivative then the area under the graph of f(x) between the points a and b is given by

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We write the area under the curve as

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Therefore

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where F is the anti-derivative of f.

Examples:

What's the area under the curve tex2html_wrap_inline67 between the points a = 0 and b = 1?

Find

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We need to find the anti-derivative of tex2html_wrap_inline73 ?

Answer: tex2html_wrap_inline75 . This is the anti-derivative, F(x).

Therefore the area under the curve is F(1) - F(0) which equals tex2html_wrap_inline81 .

This one's easy because the function defines a straight line and the area is a triangle.

Example: what's the area under the curve of tex2html_wrap_inline83 between the points 0 and 2?

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The anti-derivative is tex2html_wrap_inline85 The area is by definition tex2html_wrap_inline87 .

Interpreting the area under the curve.

First note what units the area is measured in. The units of x times the units of y.

For the velocity graph, x is measured in seconds, and velocity (y) in meters per second. Therefore the area under the velocity curve is measured in seconds tex2html_wrap_inline97 meters/seconds = meters, or in other words distance.

The area under a marginal cost curve plotted against volume is in dollars. It tells you the total cost to produce that many units.

Examples from the old exams.



Richard Waterman
Fri Aug 7 01:40:43 EDT 1998