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5.5 Logs base e

A special base for logs is the log base e. Written as ln.


ln(x) = loge(x).

So


ln(ex) = loge(ex) = x.

Taking natural logs undoes ``e'' to the power ...

A very useful interpretative fact to be explained later:

For small values of h


\begin{displaymath}\fbox{$ln(1 + h) \sim h.$ }\end{displaymath}

For example ln (1.01) is about equal to 0.01, (in fact 0.009950331).

Say we have increases of sales from time 0 to time 1, of 1%. That is $S_1 = S_0 \times 1.01$. So

\begin{displaymath}ln(S_1) = ln(S_0 \times 1.01) = ln(S_0) + ln(1.01) = ln(S_0) + ln(1 + 0.01)
\sim ln(S_0) + 0.01.\end{displaymath}

Therefore the difference in logs:

ln(S1) - ln(S0) = ln(S0) + 0.01 - ln(S0) = 0.01.

So the difference in logs gets interpreted as a ``percent change'' for small changes.


next up previous
Next: 6. Up: 5. Previous: 5.4
Richard Waterman
1999-05-06